织梦CMS - 轻松建站从此开始!

欧博ABG官网-欧博官方网址-会员登入

欧博abgProbability of exactly two heads in four coin

时间:2025-08-04 20:31来源: 作者:admin 点击: 8 次
Use binomial probability since there are only two possibilities: success and failure, where success represents getting a heads, and tails being a fail

Use binomial probability since there are only two possibilities: success and failure, where success represents getting a heads, and tails being a fail.

Let $X$ = Success (i.e. heads)

Therefore we are trying to find $P(X=2)$, which is $\binom42\cdot(0.5)^2\cdot(0.5)^2=0.375$.

Hope this helped!

The derivation of binomial probability:

Getting two heads out of 4 can be portrayed is, disregarding order:

HHTT (H=heads and T=tails)

Multiplying their probabilities will yield $(0.5)^4$, but as for ordering, we get $4!/(2!\cdot2!)$ due to repetition, which is the same as $4C2$. So our answer is $\binom42\cdot(0.5)^4$ which is $0.375$

(责任编辑:)
------分隔线----------------------------
发表评论
请自觉遵守互联网相关的政策法规,严禁发布色情、暴力、反动的言论。
评价:
表情:
用户名: 验证码:
发布者资料
查看详细资料 发送留言 加为好友 用户等级: 注册时间:2025-08-09 22:08 最后登录:2025-08-09 22:08
栏目列表
推荐内容